X+2x 2+3x 3
X2 polynomial zeros sum hence quadratic "simplify: `(3x-2)(2x-3)+\ (5x-3)(x+1)`" [新しいコレクション] x 3/x-3 x 2/x-2=2 228406-x^3+x-(x-2)(x^2+2x+4)
find the zeros of the quadratic polynomial p(x)=x2+3x+2 and hence find
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![[新しいコレクション] x 3/x-3 x 2/x-2=2 228406-X^3+x-(x-2)(x^2+2x+4)](https://i2.wp.com/useruploads.socratic.org/h0cXCaI8RnqZVqWe2sag_division_4.jpg)
